**Aptitude questions and answers on Speed Time and Distance**

1) A running man crosses a bridge of length 500 meters in 4 minutes. At what speed he is running?

- 8.5 km/hr
- 7.5 km/hr
- 9.5 km/hr
- 6.5 km/hr

The correct answer is (B)

**Explanation:**

- Distance = 500 meters
- Time = 4 minutes ⟶ 4 x 60 = 240 seconds

Speed =^{500}⁄_{240}=^{25}⁄_{12}m/s

We need answer in km/hr:

Speed in km/hr=^{25}⁄_{12}*^{18}⁄_{5}=^{90}⁄_{12}⟶^{30}⁄_{4}= 7.5 km/hr.

2) A car running at a speed of 140 km/hr reached its destination in 2 hours. If the car wants to reach at its destination in 1 hour, at what speed it needs to travel?

- 300 km/hr
- 280 km/hr
- 250 km/hr
- 240 km/hr

The correct answer is (B)

**Explanation:**

Distance to be covered = Speed x Time

= 140 * 2 = 280 km

Time = 1 hour

Required Speed =^{280}⁄_{1}= 280 km/hr (Option B).

3) A jogger is running at a speed of 15 km/hr. At what time he will cross a track of length 400 meters?

- 96 sec
- 100 sec
- 104 sec
- 110 sec

The correct answer is (A)

**Explanation:**

4) A horse covers a distance of 1500 meters in 1 minute 20 seconds. At what speed the horse is running?

- 67.2 km/hr
- 67.7 km/hr
- 67. 5 km/hr
- 67.9 km/hr

The correct answer is (C)

**Explanation:**

Distance = 1500 meters

Time = 1 minute 20 seconds ⟶60+20=80 seconds

So, Required Speed =^{1500}⁄_{80}=^{75}⁄_{4}m/s

We need an answer in km/hr:

So, Speed in km/hr =^{75}⁄_{4}*^{18}⁄_{5}= 67.5 km/hr

5) A cyclist moving at a speed of 20 km/hr crosses a bridge in 2 minutes. What is the length of the bridge?

- 555.5 m
- 444.4 m
- 777.7 m
- 666.6 m

The correct answer is (D)

**Explanation:**

The length of the bridge is equal to the distance covered by the cyclist at a speed of 20 km/hr in 2 minutes.

So, Distance = Speed * Time

Speed = 20 km/hr

Speed in m/s = 20 *^{5}⁄_{18}=^{100}⁄_{18}→^{50}⁄_{9} m/s

Time= 2 minutes →2 * 60 = 120 seconds

Required distance =^{50}⁄_{9}* 120=^{6000}⁄_{9}= 666.6 meters.

6) Two boys start running at the same time in the same direction at a speed of 10 km/hr and 12 km/hr respectively. In what time they will be 8 km apart?

- 3 hours
- 4 hours
- 5 hours
- 6 hours

The correct answer is (B)

**Explanation:**

Both the boys are in motion so we will consider relative speed to find the time.

Relative speed = 12 - 10 = 2 km/hr

Distance = 8 km

Time =^{8}⁄_{2}= 4 hours (Option B)

7) A man walking at a speed of 8 km/hr covers a certain distance in 1 hour 45 minutes. If he runs at a speed of 10 km/hr, in what time he will cover the same distance?

- 74 minutes
- 70 minutes
- 80 minutes
- 84 minutes

The correct answer is (D)

**Explanation:**

Distance = Speed * Time

Speed = 8 km/hr

Time = 1 hour 45 minutes = ^{105}⁄_{60}minutes =^{21}⁄_{12} hrs

Distance = 8 *^{21}⁄_{12}=^{168}⁄_{12}= 14 km

Time required to cover the 14 km at a speed of 10 km/hr =

Time in minutes = 1.4 * 60 = 84 minutes (Option D)

8) A horse covers a certain distance in 40 minutes if it runs at a speed of 60 km/hr. At what speed the horse can cover the same distance in 30 minutes?

- 80 km/hr
- 82 km/hr
- 84 km/hr
- 86 km/hr

The correct answer is (A)

**Explanation:**

Distance = Speed x Time

Speed = 60 km/hr

Time = 40 minutes →^{40}⁄_{60}hrs

Distance = 60 *^{40}⁄_{60}=^{2400}⁄_{60} = 40 km

Speed of horse to cover 40 km in 30 minutes or ^{30}⁄_{60}hrs would be:

9) A car moving at a speed of 75 km/hr covers a certain distance in 2 hours. If its speed is reduced by 15 km/hr, at what time it will cover the same distance?

- 135 minutes
- 140 minutes
- 150 minutes
- 155 minutes

The correct answer is (C)

**Explanation:**

Distance = speed x time

= 75 * 2 = 150 km

New speed = 75 -15= 60 km/hr

Required time =^{150}⁄_{60}=^{5}⁄_{2}hrs

We need an answer in minutes:

^{5}⁄_{2}*60=^{300}⁄_{2}= 150 minutes (Option C)

10) At his usual speed a cyclist covers a certain distance in 8 hours. When the speed of the cycle is increased by 4 km/hr the same distance can be covered in 6 hours. Find the distance.

- 92 km
- 94 km
- 96 km
- 98 km

The correct answer is (C)

**Explanation:**

Distance = speed * time

Let the distance is = X

Difference in speed is given = 4 km/hr

Therefore, ^{X}⁄_{6} -^{X}⁄_{8} = 4

= 4

X = 96 km (Option C)

11) Including stoppages the speed of a bus is 60 km/hr and excluding stoppages its speed is 65 km/hr. For how long the bus stops in an hour?

- 6 minutes
- 7 minutes
- 3 minutes
- 4 minutes

The Correct answer is (D)

**Explanation:**

The bus covers a distance of 60 km in an hour if it stops at the bus stops.

The bus covers a distance of 65 km in an hour if it does not stop at the bus stops.

Due to stoppages, it covers 5 km less.

If it does not stop it will cover 5 km more.

Time =^{5}⁄_{65}→^{1}⁄_{15}hour

We need an answer in minutes so ^{1}⁄_{15}* 60=4 minutes (Option D)

12) Two buses 200 km apart, start moving from the bus stations at the same time towards each other on parallel roads. If they cross each other at a distance of 120 km from one of the bus stations, find the ratio of their speeds.

^{4}⁄_{2}^{5}⁄_{2}^{3}⁄_{2}^{6}⁄_{2}

The Correct answer is (C)

**Explanation:**

The total distance between the bus stations is 200 km. So, when the buses cross each other the sum of the distances travelled the buses will be equal to 200 km.

We have given that buses cross each other at a distance of 120 km from one of the stations. So one bus covers a distance of 120 km and the other bus covers the rest of the distance (200-120=80km).

The ratio of their speeds will be equal to the ratio of distances covered by them.

So, the ratio of speeds = ^{120}⁄_{80}→^{3}⁄_{2}(Option C)

13) A man completes a journey in 5 hours. He completes the first half of the journey at a speed of 20 km/hr and the second half at a speed of 25 km/hr. What is the total journey in km?

- 6.4 km
- 5.4 km
- 4.4 km
- 3.4 km

The Correct answer is (B)

**Explanation:**

Let the time taken to complete the first half of the journey = X hour

∴ the time is taken to complete the second half of the journey = (5 - X)

Distance covered in first half = Distance covered in the second half

Distance covered in first half = speed * time→20*X=20X

Distance covered in second half = speed * time→25 * (5-X)

So, 20X = 25 * (5-X)

20X = 125 -25X

45X = 125

X= ^{125}⁄_{45}= 2.7 km

X is the distance covered in the first half which is equal to the distance covered in the second half.

So to get the total journey we will multiply X with 2.

Total journey in Km = 2.7 x 2 = 5.4 km (Option B)

14) If a man runs at 24 km/hr instead of 20 km/hr he could run 40 km more. Find the actual distance traveled by him.

- 100 km
- 150 km
- 200 km
- 250 km

The Correct answer is (C)

**Explanation:**

Let the actual distance traveled by man = X km

In this problem, time is the same for both situations when the man runs at 20 km/hr and 24 km/hr.

24X = 20X + 800

4X = 800

X =^{800}⁄_{4}= 200 km (Option C).

15) A bus travels 50% faster than a car. Both start moving at the same time from station P and reach station Q at the same time. The stations are 100 km apart. If on the way the bus stops at the bus stop for 10 minutes, find the speed of the car.

- 415 km/hr
- 410 km/hr
- 315 km/hr
- 300 km/hr

The Correct answer is (D)

**Explanation:**

Let the speed of the car = X km/hr

∴ the speed of the bus will be = X *^{150}⁄_{100}=^{3}⁄_{2}X

Both bus and car take equal time to reach station Q.

The bus stops for 10 minutes at the bus stop. So if the bus would not have stopped it would have reached station Q, 10 minutes earlier and the difference between the time taken by the car and bus would have been = 10 minutes or^{10}⁄_{60} hours.

3000 = 10 X

X =^{3000}⁄_{10}= 300 km/hr (Option D).

16) An airplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hour, it must travel at a speed of:

- 360 kmph
- 450 kmph
- 720kmph
- 350 kmph

The Correct answer is = 720kmph

Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]

Required speed = | 1200 x | 3 | km/hr | = 720 km/hr. | |

5 |

17) If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is:

- 50 km
- 56 km
- 76km
- 40 km

The Correct answer is 50km

Let the actual distance traveled be *x* km.

Then, | x |
= | x + 20 |

10 | 14 |

14*x* = 10*x* + 200

4*x* = 200

*x* = 50 km.

18) A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 km away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

- 150 kmph
- 130 kmph
- 120 kmph
- 170 kmph

The Correct answer is 120 kmph

Explanation:

Let the speed of the car be *x* kmph.

Then, speed of the train = | 150 | x |
= | 3 | x |
kmph. | |

100 | 2 |

75 | - | 75 | = | 125 | |

x |
(3/2)x |
10 x 60 |

75 | - | 50 | = | 5 | |

x |
x |
24 |

x = |
25 x24 | = 120 kmph. | ||

5 |

19) Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

- 14
- 10
- 13
- 15

The Correct answer is 10

Explanation

Due to stoppages, it covers 9 km less.

Time is taken to cover 9 km = | 9 | x 60 | min | = 10 min. | |

54 |

20) In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

- 3 hours
- 1hours
- 5hours
- 2 hours

The Correct answer is 3 hours

explanation:

Let the duration of the flight be *x* hours.

Then, | 600 | - | 600 | = 200 |

x |
x + (1/2) |

600 | - | 1200 | = 200 | |

x |
2x + 1 |

*x*(2*x* + 1) = 3

2*x*^{2} + *x* - 3 = 0

(2*x* + 3)(*x* - 1) = 0

*x* = 1 hr. [neglecting the -ve value of *x*]

21) A man completes a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

- 124 km
- 234 km
- 220 km
- 224 km

The Correct answer is 224 km

Explanation:

(1/2)x |
+ | (1/2)x |
= 10 |

21 | 24 |

x |
+ | x |
= 20 | |

21 | 24 |

15*x* = 168 x 20

x = |
168 x 20 | = 224 km. | ||

15 |

22) The ratio between the speeds of two trains is 7: 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:

- 83 km/hr
- 67.5 km/hr
- 87.5 km/hr
- 88 km/hr

The Correct answer is 87.5 km/hr

Explanation :

Let the speed of two trains be 7*x* and 8*x* km/hr.

Then, 8x = |
400 | = 100 | ||

4 |

x = |
100 | = 12.5 | ||

8 |

Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.

23) A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

- 72 km/hr
- 71 km/hr
- 71.11 km/hr
- 74 km/hr

The Correct answer is 71.11 km/hr

Explanation

Total time is taken = | 160 | + | 160 | hrs. | = | 9 | hrs. | |

64 | 80 | 2 |

Average speed = | 320 x | 2 | km/hr | = 71.11 km/hr. | |

9 |

24) A car traveling with of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.

- 35 km/hr
- 31 km/hr
- 35.5 km/hr
- 45 km/hr

The Correct answer is 35 km/hr

Explanation

Time taken = 1 hr 40 min 48 sec = 1 hr 40 | 4 | min = 1 | 51 | hrs = | 126 | hrs. |

5 | 75 | 75 |

Let the actual speed be *x* km/hr.

Then, | 5 | x x |
126 | = 42 |

7 | 75 |

x = |
42 x 7 x 75 | = 35 km/hr. | ||

5 x 126 |

25) In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:

- 5 kmph
- 5.7 kmph
- 7 kmph
- 1 kmph

The Correct answer is 5 kmph

Explanation

Let Abhay's speed be *x* km/hr.

Then, | 30 | - | 30 | = 3 |

x |
2x |

6*x* = 30

*x* = 5 km/hr.

26) Robert is traveling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?

- 15 kmph
- 12 kmph
- 7 kmph
- 8 kmph

The Correct answer is 12 kmph

explanation

Let the distance traveled by *x* km.

Then, | x |
- | x |
= 2 |

10 | 15 |

3*x* - 2*x* = 60

*x* = 60 km.

Time taken to travel 60 km at 10 km/hr = | 60 | hrs | = 6 hrs. | |

10 |

So, Robert started 6 hours before 2 P.M. *i.e.,* at 8 A.M.

Required speed = | 60 | kmph. | = 12 kmph. | |

5 |

27) It takes eight hours for a 600 km journey if 120 km is done by train and the rest by car. It takes 20 minutes more if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:

- 5: 2
- 9: 4
- 3 : 4
- 3 : 3

The Correct answer is 3 : 4

Explanation

Let the speed of the train be *x* km/hr and that of the car be *y* km/hr.

Then, | 120 | + | 480 | = 8 | 1 | + | 4 | = | 1 | ....(i) |

x |
y |
x |
y |
15 |

And, | 200 | + | 400 | = | 25 | 1 | + | 2 | = | 1 | ....(ii) | |

x |
y |
3 | x |
y |
24 |

Solving (i) and (ii), we get: *x* = 60 and *y* = 80.

Ratio of speeds = 60 : 80 = 3 : 4.

28) A farmer traveled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance traveled on foot is:

- 19 km
- 11 km
- 14 km
- 16 km

The Correct answer is 16 km

Explanation

Let the distance traveled on foot be *x* km.

Then, distance travelled on bicycle = (61 -*x*) km.

So, | x |
+ | (61 -x) |
= 9 |

4 | 9 |

9*x* + 4(61 -*x*) = 9 x 36

5*x* = 80

*x* = 16 km.

29) A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:

- 40
- 30
- 46
- 36

The Correct answer is 40

explanation

Let distance = *x* km and usual rate = *y* kmph.

Then, | x |
- | x |
= | 40 | 2y(y + 3) = 9x ....(i) |

y |
y + 3 |
60 |

And, | x |
- | x |
= | 40 | y(y - 2) = 3x ....(ii) |

y -2 |
y |
60 |

On dividing (i) by (ii), we get: *x* = 40.

30) Convert the 13/36 m/s into kilometers per hour?

- 1.2 kmph
- 1.3 kmph
- 1.4 kmph
- 1.5 kmph

Answer:** **B. 1.3

Explanation:** **13/36 m/s = 13/36 * 18/5

= 13/10 = 1.3 kmph

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