**Aptitude question and answer on Problems On Trains**

1. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

A. 120 metres

B. 180 meters

C. 150 meters

D. 324 meters

**Explanation:**

Speed= 60 x5/18 m/sec= 50/3 m/sec.

Length of the train = (Speed x Time).

Length of the train = 50/3x 9m = 150 m.

2. A 400m long train is running at 72 Kmph. how much time will it take to cross an electric pole?

A. 15sec

B. 20sec

C. 19sec

D. 21sec

**Explanation:**

Distance = Speed × Time

If we convert Kmph into Mpsec multiply by 5/18,

400 = 72 KmpH × time

400 = 72×5/18 × time

Time = 20Sec.

3. A 180m long train is running at 54 Kmph. how much time will it take to cross a platform of 120m long?

A. 20sec

B. 22sec

C. 19sec

D. 18sec

**Explanation:**

D = S × T

180 = 54 Kmph × Time

180= 54×5/18 × Time

Time = 20 Sec.

4. A train of length 110 meters is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A. 10

B. 8

C. 4

D. 6

**Explanation:**

Distance = 110 m

Relative speed = 60 + 6 = 66 kmph (Since both the train and the man are in moving in opposite direction)= (66*5/18) m/sec = 55/3 m/sec

Time taken to pass the man = (100*3/55) = 6 sec.

5. A train traveling at 60 kmph crosses a man in 6 seconds. What is the length of the train?

- A. 100 meters
- B. 150 meters
- C. 200 meters
- D. 250 meters

**Explanation:**

Speed in m/sec = 60 *(5/18) = 50/3 m/sec

Time taken to cross the man = 6 secs

Therefore, Distance = (50/3)* 6 = 100 metres (i.e. the length of the train).

6. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

A. 120m

B. 240m

C. 280m

D. 420m

**Explanation:**

Speed = (54 * 5/18) m/sec = 15 m/sec

Length of the train = (15 x 20) m = 300 m.

Let the length of the platform be x meters.

then, x+300 / 36 =15

= x+300 = 540

= x = 240m.

7. If the speed of a train is 20 m/sec, find the speed of the train in kmph.

A. 84 kmph

B. 72 kmph

C. 68 kmph

D. 55 kmph

**Explanation:**

Speed = Distance / Time

Speed = 20 m/sec

Speed = 20 x 18/5 m/sec

Speed = 72 kmph

Hence, the speed of the train is 72 kmph.

8. A train is 100 meters long and is running at a speed of 30 km per hour. Find the time it will take to pass a man standing at a crossing.

A. 12 seconds

B. 16 seconds

C. 14 seconds

D. 10 seconds

**Explanation:**

As we need to get an answer in seconds, so never forget to convert speed into meter per second.

Speed = 30 km/hr = 30* 5/18 m/sec

= 25/3 m/sec

Distance = length of train = 100 meter

Required time =12 seconds.

9. A train of length 250 m runs at a speed of 70 km/hr. What will be the time taken to cross any stationary object standing at the railway station?

A. 17.23 sec

B. 20 sec

C. 9.5 sec

D. 12.86 sec

**Explanation:**

Length of train = 250 m, speed of train = 70 km/hr

Length of train is always considered as distance, and hence here distance = 250 m

1) First convert speed of km/hr into m/s

Speed of train = 70 x 5/18 = 19.44 m/s

2) We know that,

Speed = Distance/Time

Time is taken to cross stationary object = 250/19.44

Time is taken to cross stationary object= 12.86 sec.

10. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

A. 120 meters

B. 180 meters

C. 324 meters

D. 150 meters

**Explanation:**

= 60 x 8/15 x 9 = 150 meters.

11. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is :

A. 9.5 km/hr

B. 10 km/hr

C. 10.5 km/hr

D. 11 km/hr

**Explanation:**

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.

Therefore, Man's rate against the current = (12.5 - 2.5) = 10 km/hr.

12. A train of length 150 meters takes 40.5 seconds to cross a tunnel of length 300 meters. What is the speed of the train in km/hr?

A. 13.33

B. 40

C. 26.67

D. 66.67

**Explanation:**

Speed = 150 + 300/40.5 m/sec = 450/40.5x18/5 km/hr = 40 km/hr.

13. Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time is taken by the slower train to cross the

faster train in seconds is

A. 48 sec

B. 52 sec

C. 58 sec

D. 66 sec

**Explanation:**

Relative sped = (60 + 90) km/hr

= [150 x 5/18] m/sec = [125 / 3] m/sec.

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = [2000 x 3/125] sec = 48 sec.

14. A train 200 m long is moving at a speed of 50km per hour. Find the time taken to pass a tree standing near the railway track.

A. 14 2/5 seconds

B. 15 seconds

C. 16 1/2 seconds

D. 17 seconds

**Explanation:**

Speed of the train = 50km/hr = 50 x 5/18 m/sec = 250/18 m/sec

Length of the train = 200 m

Time taken to cross the tree = 200 / (250/18) = 200 x 18/250 = 72/5 = 14.4 seconds

Hence the answer is 14 2/5 seconds.

15. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

A. 120m

B. 150m

C. 160m

D. 185m

**Explanation:**

Time is taken to cross a pole = time taken to cover a distance equal to its own length.

Speed of the train in m/s = 60 x 5 / 18 = (50/3) m/s.

Length of the train = Speed of the train x Time taken to cross the pole = 50/3 x 9

Length of the train = 150m.

16. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train

A. 150 meter

B. 145 meter

C. 140 meter

D. 135 meter

**Explanation:**

Speed = 60*(5/18) m/sec = 50/3 m/sec

Length of Train(Distance) = Speed * Time

=50/3*9=150meters.

17. Two trains are running in opposite directions at the same speed. The length of each train is 120 meters. If they cross each other in 12 seconds, the speed of each train (in

km/hr) is

A. 42

B. 36

C. 28

D. 20

**Explanation:**

Distance covered = 120+120 = 240 m

Time = 12 s

Let the speed of each train = v. Then relative speed = v + v = 2v

2v = distance/time = 240/12 = 20 m/s

Speed of each train = v = 20/2 = 10 m/s

= 10 × 36/10 km/hr = 36 km/hr.

18. A 400m long train is running at 72 Kmph. how much time it will take to cross an electric pole?

A. 15sec

B. 20sec

C. 19sec

D. 21sec

**Explanation:**

Formula: Distance = Speed × Time

If we convert Kmph into Mpsec multiply by 5/18,

400 = 72 KmpH × time

400 = 72×5/18 × time

Time = 20Sec.

19. The distance between the two places A and B is 570 km. A train starts from A at 50 kmph at 6 am and another starts from B at 80 kmph at 7 am towards each other. At what time will they meet?

A. 11 am

B. 3 pm

C. 8 am

D. 10 am

**Explanation:**

Let the two trains meet at a distance x km from place A

The time required by the train starting from A to cover x is x/50 hr

Time is taken by the other train starting from B to cover (570 - x) km = (570-x)/80

But the first train has started 1 hr early. So, it has traveled 50 km in this 1 hr.

Therefore, x/50 - 1= (570-x)/80

On Solving, x = 250

So, they will meet at a distance of 250 km from place A

So the time at which they will meet will be (250/50) = 5 hrs (after 6 am)

Hence, they will meet at 11 am.

20. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

A. 49 km/hr

B. 50 km/hr

C. 51 km/hr

D. 52 km/hr

**Explanation:**

Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr.

Let the speed of the train be x km/hr.

Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x = 50 km/hr.

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